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authorPablo Neira Ayuso <pablo@netfilter.org>2009-01-15 23:19:57 +0100
committerPablo Neira Ayuso <pablo@netfilter.org>2009-01-15 23:19:57 +0100
commit50339f96638eed35dac2b673b64cc6f1eb96406c (patch)
tree20dbb60fd3c41994da7cd7ad8888185c681fadb1 /include/filter.h
parentb28224b0326636ff5832b38817b7720f48070ee7 (diff)
src: rework of the hash-cache infrastructure
Currently, the caching system is implemented in a two layer architecture: hashtable (inner layer) and cache (upper layer). This patch reworks the hash-cache infrastructure to solve some initial design problems to make it more flexible, the main strong points of this patch are: * Memory handling is done in the cache layer, not in the inner hashtable layer. This removes one of the main dependencies between the hashtable and the cache classes. * Remove excessive encapsulation: the former cache used to hide a lot of details of the inner hashtable implementation. * Fix over-hashing of some operations: lookup-delete-add required three hash calculations. Similarly, the update-or-add operation required two hash calculations. Now, we calculate the hash once and re-use the value how many times as we need. This patch simplifies the caching system. As a result, we save ~130 lines of code. Small code means and less complexity means less chance to have bugs. Signed-off-by: Pablo Neira Ayuso <pablo@netfilter.org>
Diffstat (limited to 'include/filter.h')
-rw-r--r--include/filter.h11
1 files changed, 11 insertions, 0 deletions
diff --git a/include/filter.h b/include/filter.h
index 9c2cf66..72c2aa4 100644
--- a/include/filter.h
+++ b/include/filter.h
@@ -4,6 +4,7 @@
#include <stdint.h>
#include <string.h>
#include <netinet/in.h>
+#include <hash.h>
enum ct_filter_type {
CT_FILTER_L4PROTO,
@@ -17,6 +18,16 @@ enum ct_filter_logic {
CT_FILTER_POSITIVE = 1,
};
+struct ct_filter_ipv4_hnode {
+ struct hashtable_node node;
+ uint32_t ip;
+};
+
+struct ct_filter_ipv6_hnode {
+ struct hashtable_node node;
+ uint32_t ipv6[4];
+};
+
struct ct_filter_netmask_ipv4 {
uint32_t ip;
uint32_t mask;